2*3.6*h+2*3.6*h^2=(3.6^2)*h

Solution for 2*3.6*h+2*3.6*h^2=(3.6^2)*h equation:

2*3.6h+2*3.6h^2=(3.6^2)*h

We move all terms to the left:

2*3.6h+2*3.6h^2-((3.6^2)*h)=0

Wy multiply elements

6h+6h-((3.6^2)*h)=0


We calculate terms in parentheses: -((3.6^2)*h), so:

(3.6^2)*h

We multiply parentheses

3h^2

Back to the equation:

-(3h^2)


determiningTheFunctionDomain
-3h^2+6h+6h=0

We add all the numbers together, and all the variables

-3h^2+12h=0

a = -3; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-3)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-3}=\frac{-24}{-6}
=+4
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-3}=\frac{0}{-6}
=0
$